10 year olds math assignment challenge!

Math whiz

The task: Using all the digits of the year 1492 only once and in the exact order that they appear in the year 1492, construct all numbers from 1 to 100! You can use any of the following operations: square root, factorials, exponents, decimals, parentheses, negative numbers, addition, multiplication, subtraction, division.

Examples:
84 = 14 x âˆš9 x 2
90 = (1+4) x 9 x 2

We still need the following numbers calculated:
40
41
49
59
61
62
64

1 person

Monox D. I-Fly

Another game, eh? Interesting...
$$\displaystyle 40=1\times4+9^2$$
$$\displaystyle 41=(1+4)+9^2$$
$$\displaystyle 64=(1-\sqrt4+9)^2$$
I'll leave the rest to Denis McField.

1 person

skipjack

Forum Staff
Perhaps Monox D. I-Fly has been doing a headstand, as 9Â² isn't 36.

40 = 14*âˆš9 - 2
41 = -1 + 4! + 9*2
49 = (-1 + (âˆš4)^(âˆš9))^2
59 = -1 + 4*(âˆš9)/.2
61 = -1 + 4^(âˆš9) - 2
62 = 1*4^(âˆš9) - 2
64 = (1*(âˆš4)^(âˆš9))^2

3 people

Monox D. I-Fly

Oops, guess I am being stoned when doing my headstand. Well, at least my answer for 64 was correct, so my post didn't go in vain.

Math whiz

Thatâ€™s awesome!

Thank you!

Spritofmaths

Wow, you guys are smart!
Can you help me with some numbers...? I need help with 27, 31, 45, 57, 55, 58, 68, 69, 70, 79, and 83

Spritofmaths

40= 14* squrt9 -2
41=-1+4!+9*2
49=(-1+(squrt4)^(9))^2
59=-1+4*(squrt9) divided by 2

Denis

Math Team
That's a lot of numbers.
Sure is! I'll start:

1 = -1 * 4 + âˆš9 + 2
2 = -1 - 4 + 9 - 2
3 = 1 * âˆš4 + âˆš9 - 2
4 = -1 - âˆš4 + 9 - 2
5 = -1 * âˆš4 + 9 - 2