10 year olds math assignment challenge!

Nov 2017
2
1
Toronto
The task: Using all the digits of the year 1492 only once and in the exact order that they appear in the year 1492, construct all numbers from 1 to 100! You can use any of the following operations: square root, factorials, exponents, decimals, parentheses, negative numbers, addition, multiplication, subtraction, division.

Examples:
84 = 14 x √9 x 2
90 = (1+4) x 9 x 2

We still need the following numbers calculated:
40
41
49
59
61
62
64

The rest we’ve already calculated!

Thanks for your help!
 
  • Like
Reactions: 1 person
Nov 2010
2,001
132
Indonesia
Another game, eh? Interesting...
\(\displaystyle 40=1\times4+9^2\)
\(\displaystyle 41=(1+4)+9^2\)
\(\displaystyle 64=(1-\sqrt4+9)^2\)
I'll leave the rest to Denis McField.
 
  • Like
Reactions: 1 person

skipjack

Forum Staff
Dec 2006
21,481
2,470
Perhaps Monox D. I-Fly has been doing a headstand, as 9² isn't 36.

40 = 14*√9 - 2
41 = -1 + 4! + 9*2
49 = (-1 + (√4)^(√9))^2
59 = -1 + 4*(√9)/.2
61 = -1 + 4^(√9) - 2
62 = 1*4^(√9) - 2
64 = (1*(√4)^(√9))^2
 
  • Like
Reactions: 3 people
Nov 2010
2,001
132
Indonesia
Oops, guess I am being stoned when doing my headstand. Well, at least my answer for 64 was correct, so my post didn't go in vain.
 
Nov 2018
5
0
Mississauga
Wow, you guys are smart!
Can you help me with some numbers...? I need help with 27, 31, 45, 57, 55, 58, 68, 69, 70, 79, and 83
 
Nov 2018
5
0
Mississauga
Oh and here are the answers to your questions... :
40= 14* squrt9 -2
41=-1+4!+9*2
49=(-1+(squrt4)^(9))^2
59=-1+4*(squrt9) divided by 2
 

Denis

Math Team
Oct 2011
14,592
1,026
Ottawa Ontario, Canada
That's a lot of numbers.
Sure is! I'll start:

1 = -1 * 4 + √9 + 2
2 = -1 - 4 + 9 - 2
3 = 1 * √4 + √9 - 2
4 = -1 - √4 + 9 - 2
5 = -1 * √4 + 9 - 2