Hello all. I was wondering how to solve this particular problem. I am not certain I am setting it up correctly, and I think it's likely I don't have it quite right. Any help is deeply appreciated.

\(\displaystyle a= \frac{2}{3}b , c=12\)

\(\displaystyle \left (\frac{2}{3}b \right )^2+b^2=12^2\)

Next I raise the contents of my first parenthesis to the second power, then combine like terms \(\displaystyle b^2\).

Thus

\(\displaystyle \frac{4}{9}b +b^2\)

\(\displaystyle \frac{13}{9}b^2 =144\)

\Multiply both sides by reciprocal of b's coefficient

\(\displaystyle

b^2=\frac{1296}{13}\)

My guess at the solution is the same as above, just apply radical to right and remove b's 2nd power.

I appreciate any and all input. My book provides no solution, so I don't know whether this is correct or miles off the mark.

**(from textbook)**__"Use the Pythagorean Theorem to find the missing side length. Leave answer in simplest form."__\(\displaystyle a= \frac{2}{3}b , c=12\)

**(my attempt)**\(\displaystyle \left (\frac{2}{3}b \right )^2+b^2=12^2\)

Next I raise the contents of my first parenthesis to the second power, then combine like terms \(\displaystyle b^2\).

Thus

\(\displaystyle \frac{4}{9}b +b^2\)

\(\displaystyle \frac{13}{9}b^2 =144\)

\Multiply both sides by reciprocal of b's coefficient

\(\displaystyle

b^2=\frac{1296}{13}\)

My guess at the solution is the same as above, just apply radical to right and remove b's 2nd power.

I appreciate any and all input. My book provides no solution, so I don't know whether this is correct or miles off the mark.

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