# calculations of protons

#### JeffMv2

Information:
Mass of proton:$$\displaystyle 1.67×10^−27kg$$

Mass of electron: $$\displaystyle 9.11×10^−31kg$$

Proton charge $$\displaystyle +1.60×10^-19 C$$

Question:

A proton is accelerated through a voltage of 248 kV.

a) Calculate the energy of the proton in electron volt and in Joule.

b) Assuming that the mass of the proton remains the same as its rest mass, calculate the speed of the photon.

c)The proton is curved by a magnetic field of 1.5 Telsa. Calculate the radius of the curvature of its path.

My workings:

a) is 248keV.
$$\displaystyle 3.97*10^{−14 }J.$$

b) v = √(2K/m)
$$\displaystyle √(2*3.97*10^{-14})/1.67*10^{-27}) = 6.89354 * 10^6 ms^-1$$

c) r = mv/(eB) r=$$\displaystyle 1.67*10^{-19}* 6.89354 *10^6/(1.60*10^{-19}*1.5) = 4.8 * 10^6 m$$

Have I done these correctly?

#### skeeter

Math Team
(a) and (b) are ok

check the mass value of the proton you used in part (c)

#### JeffMv2

(a) and (b) are ok

check the mass value of the proton you used in part (c)
$$\displaystyle (1.67∗10^-27∗6.89354∗10^6)/(1.60∗10^−19∗1.5)=0.048$$ is it nm or m?

#### skeeter

Math Team
$$\displaystyle (1.67∗10^-27∗6.89354∗10^6)/(1.60∗10^−19∗1.5)=0.048$$ is it nm or m?
do a dimensional analysis

$\dfrac{mv}{qB} = \dfrac{(kq)(m/s)}{(C)(T)}$

what are the SI units for a Tesla?

topsquark

#### JeffMv2

do a dimensional analysis

$\dfrac{mv}{qB} = \dfrac{(kq)(m/s)}{(C)(T)}$

what are the SI units for a Tesla?
right so 0.048m

#### JeffMv2

my numerical value is correct?

Math Team