# Can someone explain me how is this notation approximately equals to Ln(n)

#### SunDrop

Ln(n) [ 1+ Ln(1+1/n) /Ln(n) ] = Ln(n)

#### topsquark

Math Team
Ln(n) [ 1+ Ln(1+1/n) /Ln(n) ] = Ln(n)
What does Ln(n) mean?

This equation seems to be a bit scrambled with the Ln(n) canceling out from both sides. Is there a typo somewhere?

-Dan

SunDrop

#### SunDrop

it's not an equation it's like the first term is approximately equals to Ln(n) . Just like sinx = x if you know what i mean ?

#### skipjack

Forum Staff
By expanding ln(1 + 1/n) in the LHS for large n, one gets ln(n)(1 + (1/n - . . . )/ln(n)), which has leading term ln(n).

(The next term would be 1/n.)

#### SunDrop

What does Ln(n) mean?

This equation seems to be a bit scrambled with the Ln(n) canceling out from both sides. Is there a typo somewhere?

-Dan
By expanding ln(1 + 1/n) in the LHS for large n, one gets ln(n)(1 + (1/n - . . . )/ln(n)), which has leading term ln(n).

(The next term would be 1/n.)
Thank youuu!