W wortel Jun 2012 12 0 Nov 18, 2015 #1 How do I determine the 4th degree polynomial with real coefficients from the following zeros of that function? (i) and 2-3i.

How do I determine the 4th degree polynomial with real coefficients from the following zeros of that function? (i) and 2-3i.

M Math Message Board tutor Jun 2014 945 191 Earth Nov 18, 2015 #2 wortel said: How do I determine the 4th degree polynomial with real coefficients from the following zeros of that function? (i) and 2-3i. Click to expand... You are given the equivalent of: 0 + i \(\displaystyle \ \ \) and 2 - 3i The other zeroes are their conjugates: 0 - i \(\displaystyle \ \ \) and 2 + 3i Your corresponding factors are: x - i x - (-i) = x + i x - (2 - 3i) x + (2 + 3i) Multiply them together.

wortel said: How do I determine the 4th degree polynomial with real coefficients from the following zeros of that function? (i) and 2-3i. Click to expand... You are given the equivalent of: 0 + i \(\displaystyle \ \ \) and 2 - 3i The other zeroes are their conjugates: 0 - i \(\displaystyle \ \ \) and 2 + 3i Your corresponding factors are: x - i x - (-i) = x + i x - (2 - 3i) x + (2 + 3i) Multiply them together.

E EvanJ Oct 2013 702 91 New York, USA Nov 18, 2015 #3 Math Message Board tutor said: x + (2 + 3i) Click to expand... Shouldn't that be x - (2 + 3i)? The other three roots were in the form x - something. I got the polynomial to be: x^4 - 4x^3 + 14x^2 - 4x + 13 Reactions: 1 person

Math Message Board tutor said: x + (2 + 3i) Click to expand... Shouldn't that be x - (2 + 3i)? The other three roots were in the form x - something. I got the polynomial to be: x^4 - 4x^3 + 14x^2 - 4x + 13

greg1313 Forum Staff Oct 2008 8,008 1,174 London, Ontario, Canada - The Forest City Nov 18, 2015 #4 EvanJ said: Shouldn't that be x - (2 + 3i)? Click to expand... Yes. EvanJ said: x^4 - 4x^3 + 14x^2 - 4x + 13 Click to expand... That's it!

EvanJ said: Shouldn't that be x - (2 + 3i)? Click to expand... Yes. EvanJ said: x^4 - 4x^3 + 14x^2 - 4x + 13 Click to expand... That's it!