I am struggling with converting formulae to the linear form Y = mX +C

For example if I have the relationship ay=b^x and I need to express this in linear form using logs, I get:

logy+ loga = xlogb

not sure how to get this to the form Y=mX+C because if I move the loga onto the other side I get:

logY = xlogb - loga which would correspond to -C

Help appreciated. Thanks.

For example if I have the relationship ay=b^x and I need to express this in linear form using logs, I get:

logy+ loga = xlogb

not sure how to get this to the form Y=mX+C because if I move the loga onto the other side I get:

logY = xlogb - loga which would correspond to -C

Help appreciated. Thanks.

Last edited by a moderator: