For several days I have been brewing on this problem at work. I can't seem to figure it out. I have solved it using a CAD design program, but I want an equation that I can use.
The situation is described by two circles, with an unequal radius. The smaller circle is placed within the bigger circle and is at one point tangential to the bigger circle. The radius of the bigger circle crosses the smaller circle twice.
I am interested in the distance X between the the circles, measured at the the radius of the bigger circle, as a function of the angle theta. I have shown an illustration of the problem below. Anyone interested can download the word file that has the illustration.
One of the ways of solving, I thought, is to express THETA2 as function of THETA1. But I didn't even manage this and I'd love to get some help on this!
Of course, I have attempted many additional things to try and solve my problem, but in order to keep the start post simple and quick, I will not go into detail of these attempts. But all I used so far is based on simple trigonometry, but as my knowledge of maths is limited, I might have kept it too simple.
The situation is described by two circles, with an unequal radius. The smaller circle is placed within the bigger circle and is at one point tangential to the bigger circle. The radius of the bigger circle crosses the smaller circle twice.
I am interested in the distance X between the the circles, measured at the the radius of the bigger circle, as a function of the angle theta. I have shown an illustration of the problem below. Anyone interested can download the word file that has the illustration.
One of the ways of solving, I thought, is to express THETA2 as function of THETA1. But I didn't even manage this and I'd love to get some help on this!
Of course, I have attempted many additional things to try and solve my problem, but in order to keep the start post simple and quick, I will not go into detail of these attempts. But all I used so far is based on simple trigonometry, but as my knowledge of maths is limited, I might have kept it too simple.
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