Does anyone knows how this is derive?

KaiL

Why is G1(y^2) = 1/(2y) ???

Country Boy

Math Team
There is no "G1" in what you post. Did you mean g'?

We are given that $$\displaystyle g(x)= \sqrt{x}= x^{1/2}$$ so that $$\displaystyle g'(x)= (1/2)x^{-1/2}. Further\(\displaystyle g(x)= \sqrt{x}= y$$ so that $$\displaystyle x= y^2$$ and $$\displaystyle x^{-1/2}= (y^2)^{-1/2}= 1/y$$ so $$\displaystyle (1/2)x^{-1/2}= 1/(2y)$$.\)