\(\displaystyle a(n!) =[a(n)]! \; \; \) , \(\displaystyle n\in \mathbb{N}\) .

\(\displaystyle a(n)\)=?

By plugging values: n=1 , a(1)=a(1)! , a(1)=1 .

Continuing like this, it gives only the solution \(\displaystyle a(n)\) equals constant.

The other solution is \(\displaystyle a(n)=n\), how to find it?

\(\displaystyle a(n)\)=?

By plugging values: n=1 , a(1)=a(1)! , a(1)=1 .

Continuing like this, it gives only the solution \(\displaystyle a(n)\) equals constant.

The other solution is \(\displaystyle a(n)=n\), how to find it?

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