Factorization

Dec 2015
1,084
169
Earth
solve x^2+x^2y+3x-10y+3xy-10=0 for x. then x^2+x^2y+3x-10y+3xy-10=(1+y)(x-x_1 )(x-x_2).
 

skipjack

Forum Staff
Dec 2006
21,481
2,470
$\begin{align*}x^2 + x^2y + 3x - 10y + 3xy - 10 &= x^2 + x^2y + 3x + 3xy - 10y - 10 \\
&= x^2(1 + y) + 3x(1 + y) - 10(1 + y) \\
&= (x^2 + 3x - 10)(y + 1) \\
&= (x + 5)(x - 2)(y + 1)\end{align*}$
 
  • Like
Reactions: topsquark