A pulley has a mass of $1.2\,kg$ and radius equal to $5\,cm$ has two bobs hanging from it as indicated in the figure from below $m_1=0.8\,kg$ and $m_2=0.6\,kg$ from both ends. The wire has a negligible mass and passes through the cavity of the pulley. The friction between the wire and the pulley allows that it moves when both masses moves. Given these conditions find the acceleration in meters per second square for the masses. Assume $g=10\,\frac{m}{s^2}$

The alternatives are as follows:

$\begin{array}{ll}

1.&1\,\frac{m}{s^2}\\

2.&2\,\frac{m}{s^2}\\

3.&3\,\frac{m}{s^2}\\

4.&4\,\frac{m}{s^2}\\

5.&5\,\frac{m}{s^2}\\

\end{array}$

I'm confused exactly on what way should I assign the signs for this object. I'm currently getting $10\,\frac{m}{s^2}$. But I don't know if is it because I'm assuming that the tension for each side is different or what?. Can someone help me with this please?.