A block of mass \(\displaystyle 10kg\) rests on a horizontal floor. The acceleration due to gravity is\(\displaystyle 9.81m/s^{2}\). The coefficient of static friction between the floor and the block is\(\displaystyle 0.2\). A horizontal force of \(\displaystyle 10N\) is applied on the block as shown in the figure. The magnitude force of friction (in N) on the block:

I can able to find \(\displaystyle F_{s}^{max} = 98 * 0.2 = 19.6\); (\(\displaystyle F_{n} = 9.8 * 10kg = 98\))