# How to solve this block physics problem?

#### Ganesh Ujwal

A block of mass $$\displaystyle 10kg$$ rests on a horizontal floor. The acceleration due to gravity is$$\displaystyle 9.81m/s^{2}$$. The coefficient of static friction between the floor and the block is$$\displaystyle 0.2$$. A horizontal force of $$\displaystyle 10N$$ is applied on the block as shown in the figure. The magnitude force of friction (in N) on the block:

I can able to find $$\displaystyle F_{s}^{max} = 98 * 0.2 = 19.6$$; ($$\displaystyle F_{n} = 9.8 * 10kg = 98$$)

After this how to proceed.

#### skeeter

Math Team
$F_s \le \mu \cdot F_N = 0.2 \cdot 10g = 19.62 \, N$

since the applied force of 10 N < 19.62 N, the reaction force of static friction is 10 N.