How to solve this block physics problem?

Aug 2014
507
1
India
A block of mass \(\displaystyle 10kg\) rests on a horizontal floor. The acceleration due to gravity is\(\displaystyle 9.81m/s^{2}\). The coefficient of static friction between the floor and the block is\(\displaystyle 0.2\). A horizontal force of \(\displaystyle 10N\) is applied on the block as shown in the figure. The magnitude force of friction (in N) on the block:



I can able to find \(\displaystyle F_{s}^{max} = 98 * 0.2 = 19.6\); (\(\displaystyle F_{n} = 9.8 * 10kg = 98\))

After this how to proceed.
 

skeeter

Math Team
Jul 2011
3,364
1,855
Texas
$F_s \le \mu \cdot F_N = 0.2 \cdot 10g = 19.62 \, N$

since the applied force of 10 N < 19.62 N, the reaction force of static friction is 10 N.