I did all the math... this is Pi. I can see it.

Sep 2019
19
1
British Columbia, Canada
We set the circle to an Area, but only because we suspect the Area to be an equal Area.

Since two shapes relevant have different sized arcs of the same radius, we know after doing the pi math using the new Pi that it's perfect, because it shows us... but we have to look.

https://postimg.cc/gallery/3ir2ttsfg/

Do we want real pi? I make mine from scratch.

Want to argue?... Show me with mathematics that you can understand, as I do.

Where's my Nobel Peace Prize?
 
Sep 2019
19
1
British Columbia, Canada
on page three you can see something interesting:

The Radius i, Squared is .375 despite using always 47 digits behind the .decimal point.

It was 3.749999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999, so I made it 3.75.
 
Sep 2019
19
1
British Columbia, Canada
CIRCLING THE STAR OF LAKSHMI
FACTS

Angle A = 112.5 degrees.
Side a = 0.707106781186547524400844362104849039284835937688

Angle B = 22.5 degrees.
Side b = 0.292893218813452475599155637895150960715164062311

Angle C = 45 degrees.
Side c = 0.541196100146196984399723205366389420061072063377

Area Triangle ABC = 0.073223304703363118899788909473787740178791015577
___________________________________________________________________
Angle D = 67.5 degrees.
Side d = 0.5

Angle E 22.5 degrees.
Side e = 0.207106781186547524400844362104849039284835937688

Angle F = 90 degrees.
Side f = 0.541196100146196984399723205366389420061072063377

Area of Triangle DEF = 0.051776695296636881100211090526212259821208984422
_____________________________________________________________________
Angle G = 125.2643896827546543153770003300187820184965784496 degrees.
Side g = 0.707106781186547524400844362104839039284835937688

Angle H = 9.735610317245345684622999669981217981503421550394 degrees.
Side h = 0.146446609406726237799577818947575480357582031155

Angle I = 45 degrees.
Side i = 0.612372435695794524549321018676472847991486870164

Area of triangle GHI = 0.036611652351681559449894454736893870089395507788
____________________________________________________________________

Angle J = 125.2643896827546543153770003300187820184965784496.
Side j = 0.707106781186547524400844362104849039284835937688

Angle K = 45 degrees.
Side k = 0.612372435695794524549321018676472847991486870164

Angle L = 9.735610317245345684622999669981217981503421550394 degrees.
Side l = 0.146446609406726237799577818947575480357582031155

Area of Triangle JKL = 0.036611652351681559449894454736893870089395507788 _____________________________________________________________________

Angle M = 112.5 degrees. Page 2
Side m = 0.612372435695794524549321018676472847991486870164

Angle N = 54.7356103172453456846229996699812179815034215504 degrees.
Side n = 0.541196100146196984399723205366389420061072063377

Angle O = 12.76438968275465431537700033001878201849657844960 degrees.
Side o = 0.146446609406726237799577818947575480357582031155

Area of Triangle MNO = 0.036611652351681559449894454736893870089395507788
______________________________________________________________________
Area of The Star of Lakshmi = 1.171572875253809902396622551580603842860656249232
Area of Circle of Radius i set to 1.171572875253809902396622551580603842860656249232
____________________________________________________________________________
Area of Wedge L within Radius i = 0.031683269365904961190261676994095928502428171413
Area of Wedge O within Radius i = 0.041540035337458157709527232479691811676362844163
_______________________________________________________________________________
Difference between Wedge L and Triangle JKL = 0.00492838298577659825963277774279794158696733637

Difference between Wedge O and Triangle MNO = 0.00492838298577659825963277774279794158696733637

NOTICE: The Equality.
_________________________________________________
WORK:

Of Solving Triangle ABC, a/sinA = b/sinB = c/sinC, to find b and c.

Angle A = 112.5 degrees, while side a = 0.707106781186547524400844362104849039284835937688

a/sinA = 0.765366864730179543456919968060797733522689124970

sinB * a/sinA = side b = 0.292893218813452475599155637895150960715164062311

sinC * a/sinA = side c = 0.541196100146196984399723205366389420061072063377
___________________________________________________________________________________
Of Solving Triangle DEF, f/sinF = e/sinE =d/sinD, to find side e and d.

Angle F = 90 degrees, whilst Side f = side c.

f/sinF = 0.541196100146196984399723205366389420061072063377

sinE * f/sinF = side e = 0.207106781186547524400844362104849039284835937688

sinD * f/sinF = side d = 0.5
_____________________________________________________________________


Of Solving Triangle GHI

Side h = side b/2. Side h = 0.146446609406726237799577818947575480357582031155

Side g known. = sqrt(2)/2 = 0.707106781186547524400844362104849039284835937688

i^2 = g^2 + h^2 - 2gh cosI

i^2 = 0.375

i = 0.612372435695794524549321018676472847991486870164... RADIUS!

Continuing, i/sinI =g/sinG = h/sinH, to find the smaller angle (H).

i/sinI = 0.866025403784438646763723170752936183471402626904

h/i/sinI = sinH = 0.169101978725762748142934768050975556986610504493

Angle H = 9.735610317245345684622999669981217981503421550394

Now, (180 degrees – angle H – angle I = angle G)

Angle G = 125.2643896827546543153770003300187820184965784496
______________________________________________________________________________
Solving Triangles JKL and MNO For Area.

Finding Area of JKL:

sinL = x/k

sinL * k = x = height = 0.103553390593273762200422181052424519642417968843

Area = 1/2 j * x

Area of Triangle JKL = 0.036611652351681559449894454736893870089395507788
___________________________________________________________________________
Finding Area of MNO:

sinO =x/n

n * sinO = x = height = 0.119573155869050134111639622200003170837190371141

Area = 1/2 m * x

Area of Triangle MNO = 0.036611652351681559449894454736893870089395507788

Area of Triangle JKL = Area of Triangle MNO.
__________________________________________________

Area Triangle ABC is 1/2 of a * e = 0.073223304703363118899788909473787740178791015577
x 16 = Area of Star of Lakshmi = 1.171572875253809902396622551580603842860656249232

With Area of Circle of Radius i set to Area of Star of Lakshmi, Pi =
3.124194334010159739724326804214943580961749997952
_______________________________________________________________________________

Finding Areas of Wedges L and O within Radius i:

(area of circle radius i = 1.171572875253809902396622551580603842860656249232)

9.735610317245345684622999669981217981503421550394 degrees/360 * Area of Circle Radius i = Area of Wedge L within Radius i = 0.031683269365904961190261676994095928502428171413

12.76438968275465431537700033001878201849657844960 degrees/360 * Area of Circle Radius i = Area of Wedge O within Radius i = 0.041540035337458157709527232479691811676362844163
_________________________________________________________________________________

Finding Wedge Segments from differences between Wedges and their Triangles:

Area of Wedge L within Radius i = 0.031683269365904961190261676994095928502428171413
Area of Wedge O within Radius i= 0.041540035337458157709527232479691811676362844163

Isolated area between Wedge L of Radius i, and Triangle JKL = 0.00492838298577659825963277774279794158696733637.

Isolated area between Wedge O of radius i, and Triangle MNO = 0.00492838298577659825963277774279794158696733637.

Equivalent differences!
__________________________________________________________________________________

Finding Area of Wedge B within Radius i:

(area ABC = 0.073223304703363118899788909473787740178791015577)
(area circle radius i = 1.171572875253809902396622551580603842860656249232)

22.5 degrees/360 * Area of Circle Radius i = Area of Wedge B within Radius i = 0.073223304703363118899788909473787740178791015577

Area ABC = Area of Wedge B within Radius i.
____________________________________________________________________

Area ABC = Area of Wedge B within Radius i.



Very sure Pi is 3.124194334010159739724326804214943580961749997952.



--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

EXTRA INFORMATION THAT I DIDN'T USE:

Finding Areas of Wedges L and O within Radius a

(area of circle radius a =1.562097167005079869862163402107471790480874998973)

9.735610317245345684622999669981217981503421550394 degrees/360 * Area of Circle Radius a =
Area of Wedge L within Radius a = 0.042244359154539948253682235992127904669904228551

12.76438968275465431537700033001878201849657844960 degrees/360 * Area of Circle Radius a =
Area of Wedge O within Radius a = 0.055386713783277543612702976639589082235150458884
__________________________________________________________________________________

Area of Wedge L within Radius a = 0.042244359154539948253682235992127904669904228551
Area of Wedge O within Radius a = 0.055386713783277543612702976639589082235150458884

Difference between Area of Wedge L of Radius a, and Area of Wedge L of Radius i =
0.010561089788634987063420558998031976167476057138

Difference between Area of Wedge O of Radius a, and Area of Wedge O of Radius i =
0.013846678445819385903175744159897270558787614721