hi every on for omega "cubic roots for 1" YazMI3JoMho what do you think ?:D:D:D

Y yoyo145 Oct 2017 15 0 Egypt May 5, 2019 #1 hi every onfor omega "cubic roots for 1"[youtube]YazMI3JoMho[/youtube] what do you think ?

M mathman Forum Staff May 2007 6,932 774 May 5, 2019 #2 I think you need to clarify what you are doing. Reactions: 1 person

Y yoyo145 Oct 2017 15 0 Egypt May 6, 2019 #3 okay the links https://math.stackexchange.com/questions/2299230/what-is-meaning-of-2n-factors [youtube]g4zTQveQuuY[/youtube] Yahia Kamal 2019

okay the links https://math.stackexchange.com/questions/2299230/what-is-meaning-of-2n-factors [youtube]g4zTQveQuuY[/youtube] Yahia Kamal 2019

Y yoyo145 Oct 2017 15 0 Egypt May 6, 2019 #4 If you don't understand anything, see video or reply to me. Last edited by a moderator: May 6, 2019

Y yoyo145 Oct 2017 15 0 Egypt May 6, 2019 #6 Hmm, I can't type omega or power in your forum?? You can save them and zoom. Or open in new tape and zoom. What is your opinion? Last edited by a moderator: May 6, 2019

Hmm, I can't type omega or power in your forum?? You can save them and zoom. Or open in new tape and zoom. What is your opinion?

skipjack Forum Staff Dec 2006 21,478 2,470 May 6, 2019 #8 As Ï‰ + Ï‰Â² = -1, (1 - Ï‰)(1 - Ï‰Â²) = 1 - Ï‰ - Ï‰Â² + Ï‰Â³ = 2 + 1 = 3. Similarly, each successive pair of factors has product 3. Reactions: 1 person

As Ï‰ + Ï‰Â² = -1, (1 - Ï‰)(1 - Ï‰Â²) = 1 - Ï‰ - Ï‰Â² + Ï‰Â³ = 2 + 1 = 3. Similarly, each successive pair of factors has product 3.

Y yoyo145 Oct 2017 15 0 Egypt May 6, 2019 #9 But why you are taking successive pairs? I think 2n means the number of our factors. Last edited by a moderator: May 6, 2019

skipjack Forum Staff Dec 2006 21,478 2,470 May 6, 2019 #10 As there are 2n factors, there are n pairs of factors. I used successive pairs of factors because each such pair has product 3.

As there are 2n factors, there are n pairs of factors. I used successive pairs of factors because each such pair has product 3.