# I found new solution for this problem

#### yoyo145

Okay, but what if the given was only three brackets?

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#### skipjack

Forum Staff
If the number of factors is odd, the right-hand side will need to involve Ï‰.

#### yoyo145

If the number of factors is odd, the right-hand side will need to involve Ï‰.
The number of factors is even: 2n

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#### skipjack

Forum Staff
I took "only three brackets" to mean "only three factors", which won't arise (because 2n is even).

#### yoyo145

I took "only three brackets" to mean "only three factors", which won't arise (because 2n is even).
can you solve the new problem and explain what do you mean ?
prove that:

=1

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#### skipjack

Forum Staff
What new problem? For problem (8), consider the factors in successive pairs, as already described. Can you try it for yourself and post your work?

#### yoyo145

What new problem? For problem (8), consider the factors in successive pairs, as already described. Can you try it for yourself and post your work?
Okay, but really I don't understand why 2n factors means successive pairs. When I read it, I think the question mean to 8 factor or to 10 factors.

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#### skipjack

Forum Staff
The question doesn't specify successive pairs. I suggested successive pairs because that's a convenient way to find the product.

#### yoyo145

So your answer is not general because if you get three factors we will not figure out the right answer.