I found new solution for this problem

Oct 2017
15
0
Egypt
Okay, but what if the given was only three brackets?
59934030_653367038444064_1692238877223288832_n.jpg
 
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skipjack

Forum Staff
Dec 2006
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If the number of factors is odd, the right-hand side will need to involve ω.
 

skipjack

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Dec 2006
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I took "only three brackets" to mean "only three factors", which won't arise (because 2n is even).
 
Oct 2017
15
0
Egypt
I took "only three brackets" to mean "only three factors", which won't arise (because 2n is even).
can you solve the new problem and explain what do you mean ?
prove that:
59934030_653367038444064_1692238877223288832_n.jpg
=1
 
Last edited:

skipjack

Forum Staff
Dec 2006
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What new problem? For problem (8), consider the factors in successive pairs, as already described. Can you try it for yourself and post your work?
 
Oct 2017
15
0
Egypt
What new problem? For problem (8), consider the factors in successive pairs, as already described. Can you try it for yourself and post your work?
Okay, but really I don't understand why 2n factors means successive pairs. When I read it, I think the question mean to 8 factor or to 10 factors.
 
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skipjack

Forum Staff
Dec 2006
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The question doesn't specify successive pairs. I suggested successive pairs because that's a convenient way to find the product.
 
Oct 2017
15
0
Egypt
So your answer is not general because if you get three factors we will not figure out the right answer.

Please check my proof.
 
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skipjack

Forum Staff
Dec 2006
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There can't be just three factors because it is stated that there are 2n factors.