Okay, but what if the given was only three brackets?

Y yoyo145 Oct 2017 15 0 Egypt May 6, 2019 #11 Okay, but what if the given was only three brackets? Last edited: May 6, 2019

skipjack Forum Staff Dec 2006 21,468 2,464 May 6, 2019 #12 If the number of factors is odd, the right-hand side will need to involve Ï‰.

Y yoyo145 Oct 2017 15 0 Egypt May 6, 2019 #13 skipjack said: If the number of factors is odd, the right-hand side will need to involve Ï‰. Click to expand... The number of factors is even: 2n Last edited by a moderator: May 7, 2019

skipjack said: If the number of factors is odd, the right-hand side will need to involve Ï‰. Click to expand... The number of factors is even: 2n

skipjack Forum Staff Dec 2006 21,468 2,464 May 7, 2019 #14 I took "only three brackets" to mean "only three factors", which won't arise (because 2n is even).

Y yoyo145 Oct 2017 15 0 Egypt May 7, 2019 #15 skipjack said: I took "only three brackets" to mean "only three factors", which won't arise (because 2n is even). Click to expand... can you solve the new problem and explain what do you mean ? prove that: =1 Last edited: May 7, 2019

skipjack said: I took "only three brackets" to mean "only three factors", which won't arise (because 2n is even). Click to expand... can you solve the new problem and explain what do you mean ? prove that: =1

skipjack Forum Staff Dec 2006 21,468 2,464 May 7, 2019 #16 What new problem? For problem (8), consider the factors in successive pairs, as already described. Can you try it for yourself and post your work?

What new problem? For problem (8), consider the factors in successive pairs, as already described. Can you try it for yourself and post your work?

Y yoyo145 Oct 2017 15 0 Egypt May 7, 2019 #17 skipjack said: What new problem? For problem (8), consider the factors in successive pairs, as already described. Can you try it for yourself and post your work? Click to expand... Okay, but really I don't understand why 2n factors means successive pairs. When I read it, I think the question mean to 8 factor or to 10 factors. Last edited by a moderator: May 7, 2019

skipjack said: What new problem? For problem (8), consider the factors in successive pairs, as already described. Can you try it for yourself and post your work? Click to expand... Okay, but really I don't understand why 2n factors means successive pairs. When I read it, I think the question mean to 8 factor or to 10 factors.

skipjack Forum Staff Dec 2006 21,468 2,464 May 7, 2019 #18 The question doesn't specify successive pairs. I suggested successive pairs because that's a convenient way to find the product.

The question doesn't specify successive pairs. I suggested successive pairs because that's a convenient way to find the product.

Y yoyo145 Oct 2017 15 0 Egypt May 7, 2019 #19 So your answer is not general because if you get three factors we will not figure out the right answer. Please check my proof. Last edited by a moderator: May 7, 2019

So your answer is not general because if you get three factors we will not figure out the right answer. Please check my proof.

skipjack Forum Staff Dec 2006 21,468 2,464 May 7, 2019 #20 There can't be just three factors because it is stated that there are 2n factors.