largest number using 0 to 9 digits without using two consecutive factorial;

is it the largest number?

(0!+12)^3!^4!^5!^6!^7!^8!^9!

Unclear!

must digits be in ascending/descending/whatever order?

you're showing (0! + 12) : 12 is not a digit;

problem seems to say "using each digit once and by itself..."

Is 8! * 9! considered as two consecutive factorials?

There is a * between them...

Edit: whadda hell is a "wff" ??? ; I'm used to "wtf"