# Limits

#### raven2k7

Hi I need to answer the following equation:

$$\displaystyle \lim_{x\to2}$$ (xÂ³ + 3x - 1) =

x3 = x to the power of 3

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#### JeffM1

Show x to the power of 3 as x^3.

One way to answer this question is to use the laws of limits.

$\displaystyle \lim_{x \rightarrow a} f(x) = b, \ \lim_{x \rightarrow a} g(x) = c, \text { and } h(x) = f(x) + g(x) \implies \lim_{x \rightarrow a} h(x) = b + c.$

$\displaystyle \lim_{x \rightarrow a} f(x) = b, \ \lim_{x \rightarrow a} g(x) = c, \text { and } h(x) = f(x) - g(x) \implies \lim_{x \rightarrow a} h(x) = b - c.$

$\displaystyle \lim_{x \rightarrow a} f(x) = b, \ \lim_{x \rightarrow a} g(x) = c, \text { and } h(x) = f(x) * g(x) \implies \lim_{x \rightarrow a} h(x) = bc.$

$\displaystyle \lim_{x \rightarrow a} f(x) = b, \ \lim_{x \rightarrow a} g(x) = c, \ c \ne 0, \text { and } h(x) = \dfrac{f(x)}{g(x)} \implies \lim_{x \rightarrow a} h(x) = \dfrac{b}{c}.$

1 person

#### raven2k7

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#### skipjack

Forum Staff
What do you get by replacing each "x" in "xÂ³ + 3x - 1" with "2" and evaluating the result?

#### v8archie

Math Team
The answer is that it's time for you to do some work for yourself.

3 people

#### zylo

Informally, substitute x = 2

Formally, limit of a sum is sum of its summands limits, and limit of a product is product of its factors limits. limit x = 2.

4 people

#### raven2k7

Informally, substitute x = 2

Formally, limit of a sum is sum of its summands limits, and limit of a product is product of its factors limits. limit x = 2.
by the way, none of those results were correct. lol

#### [email protected]

by the way, none of those results were correct. lol

1 person

#### v8archie

Math Team
He is clearly clever enough that he doesn't need any help.

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