How does the top of part B become the bottom of part B?

S shreddinglicks Oct 2014 46 2 NJ May 23, 2019 #1 How does the top of part B become the bottom of part B? Attachments Capturex.jpg 21.2 KB Views: 21

skipjack Forum Staff Dec 2006 21,478 2,470 May 23, 2019 #2 It's long division, bearing in mind that further terms can be ignored (as they wouldn't affect the final expression).

It's long division, bearing in mind that further terms can be ignored (as they wouldn't affect the final expression).

topsquark Math Team May 2013 2,518 1,049 The Astral plane May 23, 2019 #3 You can also see this as a Maclaurin series in powers of D: \(\displaystyle \dfrac{1}{1 - \dfrac{D}{3} + \dfrac{4D^2}{9}} \approx 1 + \dfrac{D}{3} - \dfrac{D^2}{3}\) To second order in D. -Dan Reactions: 1 person

You can also see this as a Maclaurin series in powers of D: \(\displaystyle \dfrac{1}{1 - \dfrac{D}{3} + \dfrac{4D^2}{9}} \approx 1 + \dfrac{D}{3} - \dfrac{D^2}{3}\) To second order in D. -Dan

S shreddinglicks Oct 2014 46 2 NJ May 24, 2019 #4 skipjack said: It's long division, bearing in mind that further terms can be ignored (as they wouldn't affect the final expression). Click to expand... I tried to perform this long division but I am not getting the proper answer. I keep getting a remainder that is my original denominator.

skipjack said: It's long division, bearing in mind that further terms can be ignored (as they wouldn't affect the final expression). Click to expand... I tried to perform this long division but I am not getting the proper answer. I keep getting a remainder that is my original denominator.