manipulating differential operator

skipjack

Forum Staff
Dec 2006
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It's long division, bearing in mind that further terms can be ignored (as they wouldn't affect the final expression).
 

topsquark

Math Team
May 2013
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The Astral plane
You can also see this as a Maclaurin series in powers of D:
\(\displaystyle \dfrac{1}{1 - \dfrac{D}{3} + \dfrac{4D^2}{9}} \approx 1 + \dfrac{D}{3} - \dfrac{D^2}{3}\) To second order in D.

-Dan
 
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Oct 2014
46
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NJ
It's long division, bearing in mind that further terms can be ignored (as they wouldn't affect the final expression).
I tried to perform this long division but I am not getting the proper answer. I keep getting a remainder that is my original denominator.