# non-homogeneous recurrence problem

#### topsquark

Math Team
Come on, can anybody solve this step by step? I am really struggling with this problem.

v8archie has been on task this whole time! See post #2. If you don't know how to use it then ask.

-Dan

#### v8archie

Math Team
Well.. and how does that become $$\displaystyle \sqrt{6}$$?
I believe that I told you that the modulus (absolute value, norm) of those complex numbers is $\sqrt6$. If you don't understand that much, you have no business trying to solve the recurrence relation in my opinion. It's a prerequisite.

1 person

#### SuperNova1250

You kept repeating stuff that didn't make any sense, giving me the particular solution when I had a problem with the homogeneous part.

I came to the forum to ask for help, not for someone to show off.

When I asked for the part that I was struggling with, you didn't help me one bit and continue to post answers that didn't solve my problem, after which I asked you to elaborate on the stuff I didn't understand, you became downright rude.

If you can't explain or don't have time to, please restrain yourself from posting unproductive answers.

I have solved the problem myself.

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#### v8archie

Math Team
Well done. That's the general idea - much better than asking somebody else to do it for you. The thing that stopped me advancing on the problem was that you demonstrated zero understanding of the basic ideas that I was talking about - as I said before, pre-requisites for the problem.