7 777HENRY Jul 2014 8 0 Taiwan Sep 10, 2017 #1 P: Î¶(sáµ¢)=0 Q: sáµ¢=Ïƒ+it R: tâ‰ 0 S: Ïƒ=1/2 A: Pâ‰¡[Qâ‰¡(Râ‰¡S)] It is that Î¶(1/2)=0 if the Proposition A doesn't hold, but actually, Î¶(1/2)â‰ˆ-1.4603545; therefore RH does hold.
P: Î¶(sáµ¢)=0 Q: sáµ¢=Ïƒ+it R: tâ‰ 0 S: Ïƒ=1/2 A: Pâ‰¡[Qâ‰¡(Râ‰¡S)] It is that Î¶(1/2)=0 if the Proposition A doesn't hold, but actually, Î¶(1/2)â‰ˆ-1.4603545; therefore RH does hold.
M mathman Forum Staff May 2007 6,913 762 Sep 11, 2017 #2 I am not sure what you are trying to say. However (using your notation) the Riemann hypothesis states that all zeroes for 0<Ïƒ<1 are on the line Ïƒ=1/2+it, not necessarily for t=0.
I am not sure what you are trying to say. However (using your notation) the Riemann hypothesis states that all zeroes for 0<Ïƒ<1 are on the line Ïƒ=1/2+it, not necessarily for t=0.
C Country Boy Math Team Jan 2015 3,261 899 Alabama Oct 20, 2017 #3 I presume you mean "for 0< |Ïƒ|<1".
M mathman Forum Staff May 2007 6,913 762 Oct 20, 2017 #4 Country Boy said: I presume you mean "for 0< |Ïƒ|<1". Click to expand... No, sorry. I meant all Ïƒ = x + iy where 0 < x < 1.
Country Boy said: I presume you mean "for 0< |Ïƒ|<1". Click to expand... No, sorry. I meant all Ïƒ = x + iy where 0 < x < 1.