Of the 16 possibilities, (1,2), (1,4), (3,2) and (3,4) occur within both event A and event B, so P(Aâ‹‚B) = 25%.

Of the 16 possibilities, (1,1), (1,2), (1,3), (1,4), (2,1), (2, 3), (3,1), (3,2), (3,3), (3,4), (4,1) and (4,3) occur within event B or event C, so P(Bâ‹ƒC) = 75%.

Get the idea?

For P(D'), list the possibilities that do not occur within event D.

In each case, divide the number of possibilities you listed by 16, then multiply the result by 100% to get the answer in the required form.